Aufgabe S 43 Abitur 1991

a) $W_{el} = W_{kin}$

$qU = {1 \over 2} m v^2$

$v = \sqrt{ 2 {q \over m} U } = 1,38 * 10^5 {m \over s}$

b) $y = {1 \over 2} a t^2; a = {F \over m} = {{E*q} \over m} = {{U*q} \over {d*m}}; t = {l \over v_0}$

$y = {1 \over 2} {{U*q} \over {d*m}} \left( {l \over v_0} \right)^2 = 8.89 * 10^{-3} m$

${F_{el} \over F_G} = {{q*E} \over {m*g}}= {{q*U} \over {m*g*d}} = 2,19 * 10^{10}$