Seite 51 8: Unterschied zwischen den Versionen
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− | | <math> | + | | <math>f_1(x)= 3x + \frac{1}{x^2} </math>|| x<sub>1</sub> = -2|| m = -5 |
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− | | | + | | <math>f_2(x)= 2,4x^2 - \frac{1}{2} x^4</math>|| x<sub>2</sub> = -1|| m = 1,6 |
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− | | | + | | <math>f_3(x)= - \frac{5}{x^2} -4x </math> || x<sub>3</sub> = 0|| m = 2,7 |
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− | | | + | | <math>f_4(x)= x^3 - 2x^2 </math> || x<sub>4</sub> = 1|| m = 0,9 |
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− | | | + | | <math>f_5(x)= 3 - \frac{3}{x^2} </math>|| x<sub>5</sub> = 1,4|| m = 0 |
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− | | | + | | <math>f_6(x)= 4x^3 - 3x^4 </math> || x<sub>6</sub> = 2|| m = -1,5 |
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<div class="zuordnungs-quiz"> | <div class="zuordnungs-quiz"> | ||
{| | {| | ||
− | | | + | | <math>f_1(x)= 3x + \frac{1}{x^2} </math>|| x<sub>1</sub> = -2|| m = -5 |
− | + | ||
− | + | ||
|- | |- | ||
− | | | + | | <math>f_2(x)= 2,4x^2 - \frac{1}{2} x^4</math>|| x<sub>2</sub> = -1|| m = 1,6 |
|- | |- | ||
− | | | + | | <math>f_3(x)= - \frac{5}{x^2} -4x </math> || x<sub>3</sub> = 0|| m = 2,7 |
|- | |- | ||
− | | | + | | <math>f_4(x)= x^3 - 2x^2 </math> || x<sub>4</sub> = 1|| m = 0,9 |
|- | |- | ||
− | | | + | | <math>f_5(x)= 3 - \frac{3}{x^2} </math>|| x<sub>5</sub> = 1,4|| m = 0 |
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− | | | + | | <math>f_6(x)= 4x^3 - 3x^4 </math> || x<sub>6</sub> = 2|| m = -1,5 |
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Version vom 12. November 2009, 20:27 Uhr
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