M6 Ermittlung gemeinsamer Nenner

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Theorie: Buch S. 67

Aufgaben

  •  \frac{2}{3} + \frac{1}{5} =
 \frac{10}{15} + \frac{3}{15} = \frac{13}{15}


  •  \frac{2}{5} + \frac{4}{15} =
 \frac{6}{15} + \frac{4}{15} = \frac{10}{15} = \frac{2}{3}


  •  \frac{8}{15} + \frac{3}{20} =
 \frac{32}{60} + \frac{9}{60} = \frac{41}{60} NR: 15 = 3 \cdot 5; 20 = 2 \cdot 2 \cdot 5; HN=2 \cdot 2 \cdot 3 \cdot 5 = 60


  •  \frac{9}{14} - \frac{2}{21} =
 \frac{27}{42} - \frac{4}{42} = \frac{23}{42} NR: 14 = 2 \cdot 7; 21 = 3 \cdot 7; HN=2 \cdot 3 \cdot 7 = 42


  •  ( \frac{11}{12} - \frac{13}{20} ) + \frac{11}{120} =
 left( \frac{110}{120} - \frac{78}{120} right) + \frac{11}{120} = \frac{32}{120} + \frac{11}{120} = \frac{43}{120}


  •  \frac{8}{9} - ( \frac{7}{8} ) - \frac{5}{36} ) =
 \frac{64}{72} - ( \frac{63}{72} ) - \frac{10}{72} ) = \frac{64}{72} - \frac{53}{72} = \frac{11}{72}