Hausaufgabe vom 02.10.2009: Unterschied zwischen den Versionen

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S. 19/2
 
S. 19/2
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a) 3:6 = <math> {3 \over 6} = {1 \over 2}</math>
 
a) 3:6 = <math> {3 \over 6} = {1 \over 2}</math>
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b) 11:99 = <math> {11 \over 99} = {1 \over 9}</math>
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c) 51:48 = <math> {51 \over 48} = {17 \over 16}</math>
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d) 23:92 = <math> {23 \over 92} = {1 \over 4}</math>
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e) 9:6 = <math> {9 \over 6} = {3 \over 2}</math>
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f) 72:48 = <math> {72 \over 48} = {3 \over 2}</math>
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g) 96:37 = <math> {96 \over 37}</math>
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h) 213:99 = <math> {213 \over 99} = {71 \over 33}</math>

Aktuelle Version vom 4. Oktober 2009, 18:40 Uhr

S. 19/2

a) 3:6 = {3 \over 6} = {1 \over 2}

b) 11:99 = {11 \over 99} = {1 \over 9}

c) 51:48 = {51 \over 48} = {17 \over 16}

d) 23:92 = {23 \over 92} = {1 \over 4}

e) 9:6 = {9 \over 6} = {3 \over 2}

f) 72:48 = {72 \over 48} = {3 \over 2}

g) 96:37 = {96 \over 37}

h) 213:99 = {213 \over 99} = {71 \over 33}

Von „http://rmg.zum.de/index.php?title=6a_2009_10/Hausaufgabe_vom_02.10.2009&oldid=20712“