Hausaufgabe vom 28.10.2009: Unterschied zwischen den Versionen
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* b)2,04 = <math> 2 {4 \over 100} = 2 {1 \over 25}</math> | * b)2,04 = <math> 2 {4 \over 100} = 2 {1 \over 25}</math> | ||
<br> | <br> | ||
| − | * c)31,45 = <math> 31 {45 \over 100} = 31 {9 \over | + | * c)31,45 = <math> 31 {45 \over 100} = 31 {9 \over 20}</math> |
<br> | <br> | ||
* d)0,0016 = <math> {16 \over 10000} = {8 \over 5000}= {4 \over 2500}= {2 \over 1250}= {1 \over 625}</math> | * d)0,0016 = <math> {16 \over 10000} = {8 \over 5000}= {4 \over 2500}= {2 \over 1250}= {1 \over 625}</math> | ||
Aktuelle Version vom 30. Oktober 2009, 10:55 Uhr
S. 29/3
- a)1,3
- b)0,37
- c)0,003
- d)12,346
- e)3,09
- f)0,027
- g)4,007
- h)0,0031
S. 29/4
- a)1,2 =
- b)2,04 =
- c)31,45 =
- d)0,0016 =
- e)0,375 =
- f)4,625 =
